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Simple Harmonic Motion

Specification

info

Standard level and higher level: 3 hours Students should understand: -conditions that lead to simple harmonic motion

  • the defining equation of simple harmonic motion as given by a = -ω2x\omega^2 x
  • a particle undergoing simple harmonic motion can be described using time period TT, frequency ff, angular frequency ω\omega, amplitude, equilibrium position, and displacement
  • the time period in terms of frequency of oscillation and angular frequency as given by T=1/fT = 1/f = 2πω2\pi \omega
  • the time period of a mass-spring system as given by T=2πmkT = 2\pi \sqrt{\frac mk}
  • the time period of a simple pendulum as given by T=2π sqrtlgT = 2\pi\ sqrt{\frac lg}
  • a qualitative approach to energy changes during one cycle of an oscillation. -dditional higher level: 4 hours -tudents should understand:
  • that a particle undergoing simple harmonic motion can be described using phase angle
  • that problems can be solved using the equations for simple harmonic motion as given by x=x0sin(ωt+Φ)>v=ωx0cos(ωt+Φ)>v=±ωx02x2>ET=12mω2x02>EP=12mω2×2.x = x_0 \sin (\omega t + \Phi) >v = \omega x_0 cos (\omega t + \Phi ) >v = \pm \omega x_0 2 -x 2 >E_T = \frac{12}{m} \omega 2 x0 2 > E_P = \frac{12}{m} \omega 2 \times 2 .

Fundamental Principles

Simple Harmonic Motion (SHM) is a periodic oscillation about a stable equilibrium position, characterized by a restoring force FF directly proportional to the displacement xx from equilibrium and directed oppositely to the displacement. This yields Newton's second law:

FxFnet=kx=md2xdt2,\begin{aligned} F \propto x \\ F_{\text{net}} = -kx = m \frac{d^2x}{dt^2}, \end{aligned}

where k>0k > 0 is the stiffness constant (e.g., spring constant). Rearranged as the equation of motion:

d2xdt2+ω2x=0,ω=km.(1)\frac{d^2x}{dt^2} + \omega^2 x = 0, \quad \omega = \sqrt{\frac{k}{m}}. \tag{1}

Here, ω\omega is the angular frequency (rad·s⁻¹), governing the system's temporal evolution.

Key Characteristics:

  • Equilibrium Position: Point where net force vanishes (Fnet=0F_{\text{net}} = 0).
  • Amplitude (AA): Maximum displacement from equilibrium (xmax=A|x|_{\text{max}} = A).
  • Isochrony: Period TT is amplitude-independent for ideal SHM.

Conditions for Ideal SHM:

  1. Restoring force obeys Hooke’s law: F=kxF = -kx.
  2. Zero dissipative forces (undamped motion).
  3. Constant total mechanical energy.

Kinematic Relations

The general solution to Equation (1) is:

x(t)=Acos(ωt+ϕ0),(2)x(t) = A \cos(\omega t + \phi_0), \tag{2}

where ϕ0\phi_0 is the initial phase angle. Velocity vv and acceleration aa follow by differentiation:

v(t)=dxdt=ωAsin(ωt+ϕ0),(3)v(t) = \frac{dx}{dt} = -\omega A \sin(\omega t + \phi_0), \tag{3} a(t)=d2xdt2=ω2Acos(ωt+ϕ0)=ω2x.(4)a(t) = \frac{d^2x}{dt^2} = -\omega^2 A \cos(\omega t + \phi_0) = -\omega^2 x. \tag{4}

Phase Relationships:

  • Displacement-Velocity: v=±ωA2x2v = \pm \omega \sqrt{A^2 - x^2} (from energy conservation).
  • Displacement-Acceleration: a=ω2xa = -\omega^2 x (definitive property of SHM).
  • Extrema:
    • vmax=ωA|v|_{\text{max}} = \omega A at x=0x = 0 (equilibrium).
    • amax=ω2A|a|_{\text{max}} = \omega^2 A at x=±Ax = \pm A (max displacement).

Graphical Interpretation:

  • x(t)x(t), v(t)v(t), and a(t)a(t) are phase-shifted sinusoids (Figure 1).
  • a(t)a(t) is inverted relative to x(t)x(t) due to axa \propto -x.

Energy Conservation

Total mechanical energy EtotalE_{\text{total}} is conserved:

Etotal=K+U=12mv2+12kx2.(5)E_{\text{total}} = K + U = \frac{1}{2}mv^2 + \frac{1}{2}kx^2. \tag{5}

Substituting Equations (2)–(4) yields:
Kinetic Energy (KK):

K=12mω2A2sin2(ωt+ϕ0)=12mω2(A2x2).(6)K = \frac{1}{2}m \omega^2 A^2 \sin^2(\omega t + \phi_0) = \frac{1}{2}m\omega^2 (A^2 - x^2). \tag{6}

Potential Energy (UU):

U=12kx2=12mω2x2.(7)U = \frac{1}{2}kx^2 = \frac{1}{2}m\omega^2 x^2. \tag{7}

Total Energy:

Etotal=12kA2=12mω2A2.(8)E_{\text{total}} = \frac{1}{2}kA^2 = \frac{1}{2}m\omega^2 A^2. \tag{8}

Energy Oscillations:

  • Kmax=EtotalK_{\text{max}} = E_{\text{total}} at x=0x = 0.
  • Umax=EtotalU_{\text{max}} = E_{\text{total}} at x=±Ax = \pm A.

Example Systems

Simple Pendulum

Description: Point mass mm suspended on a massless string of length LL in gravitational field gg.
Equation of Motion:
For small θ\theta (sinθθ\sin\theta \approx \theta):

d2θdt2+gLθ=0.(9)\frac{d^2\theta}{dt^2} + \frac{g}{L}\theta = 0. \tag{9}

This matches Equation (1) with ω=g/L\omega = \sqrt{g/L}.
Period:

T=2πω=2πLg.(10)T = \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{L}{g}}. \tag{10}

Properties:

  • TLT \propto \sqrt{L}; T1/gT \propto 1/\sqrt{g}; independent of mm and AA (for θ1\theta \ll 1 rad).

Mass-Spring System

Description: Mass mm attached to a spring of stiffness kk.
Equation of Motion:
From Hooke’s law:

md2xdt2=kx    d2xdt2+kmx=0.(11)m\frac{d^2x}{dt^2} = -kx \implies \frac{d^2x}{dt^2} + \frac{k}{m}x = 0. \tag{11}

Period:

T=2πmk.(12)T = 2\pi \sqrt{\frac{m}{k}}. \tag{12}

Properties:

  • TmT \propto \sqrt{m}; T1/kT \propto 1/\sqrt{k}; independent of AA.

Angular Frequency and Phase

Angular Frequency (ω\omega):

ω=2πf=2πT,(13)\omega = 2\pi f = \frac{2\pi}{T}, \tag{13}

where ff is linear frequency (Hz). Converts temporal periodicity to angular speed.

Phase Angle (ϕ\phi):
Generalizes Equation (2):

x(t)=Acos(ωt+ϕ0).x(t) = A \cos(\omega t + \phi_0).
  • Phase Difference (Δϕ\Delta\phi): Temporal shift between two SHMs: Δϕ=ωΔt=2πΔtT.(14)\Delta\phi = \omega \Delta t = \frac{2\pi \Delta t}{T}. \tag{14}
  • Measured in radians (1 rad ≈ 57.3°).

Summary of Key Equations

QuantityExpression
Displacementx=Acos(ωt+ϕ0)x = A \cos(\omega t + \phi_0)
Velocityv=ωAsin(ωt+ϕ0)v = -\omega A \sin(\omega t + \phi_0)
Accelerationa=ω2xa = -\omega^2 x
Angular Frequencyω=k/m\omega = \sqrt{k/m} (spring), ω=g/L\omega = \sqrt{g/L} (pendulum)
PeriodT=2π/ωT = 2\pi / \omega
Kinetic EnergyK=12mω2(A2x2)K = \frac{1}{2}m\omega^2(A^2 - x^2)
Potential EnergyU=12mω2x2U = \frac{1}{2}m\omega^2 x^2
Total EnergyEtotal=12mω2A2E_{\text{total}} = \frac{1}{2}m\omega^2 A^2